Q.1 The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height h from rest without sliding is (a) 10 7 g h − − − − √ 10 7 g h (b) g h − − √ g h (c) 6 5 g h − − − − √ 6 5 g h (d) 4 3 g h − − − − √ Answer:- Here the sphere is rolling , Hence we will use formula , V² = (2gh)/(1+K²/R²) Here the term K²/R² , is the multiplier of moment of inertia,(MI). The MI for the solid sphere is 2/5 mR² Therefore value of the multiplier in this case will be 2/5. You will get extra information from the page given below. After calculation we will conclude option a. as correct one.